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Contrast LF

Contrast holds when the two DUs attached have similar semantic structures, but contrasting themes, i.e. sentence topics, or when one constituent negates a default consequence of the other.

LL (linguistic source -> linguistic target)

Rule(s):

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def LF_Contrast_L_L(row):
    l=0
    if row.source_emitter == row.target_emitter and row.distance == 1:
        if any(x in row.target_text.lower() for x in ["but", "well", "though", "unfortunately", "however","unlike", "not your fault", "don't take that the wrong way", "i don't think"]) or (row.source_dialogue_act == "Counteroffer" and row.target_dialogue_act == "Offer"): 
            l=1
    return l

Application of rules to candidates:

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#1 -- get dialogues
finals = []
dialogues = cands.dialogue_num.drop_duplicates()

for d in tqdm(dialogues):
 
    # 2 -- get segment list
    seg_list = get_seg_list(cands[cands.dialogue_num == d])

    # 3 -- create seg pairs list
    seg_pairs = []
    for i, s in enumerate(seg_list):
        for n in [j for j in reversed(range((i+1)-20, i+1)) if j>=0]:
            try:
                seg_pairs.append((seg_list[n], seg_list[i+1]))   
            except IndexError:
                pass
            
    # 4 -- for each pair, pull row and append rules

    for s in seg_pairs:
        row = cands[(cands.source_id == s[0]) & (cands.target_id == s[1])]
        if row.empty:
            continue
        else:
            r_index = row.index[0]
            row = row.iloc[0]
        
        # make sure that if any backwards links exist they are also 0
            
        backwards = cands[(cands.source_id == s[1]) & (cands.target_id == s[0])]
        if backwards.shape[0] > 0:
            b_index = backwards.index[0]
            finals.append((b_index, -1))
            
        
        #we only look at ling --> ling cases
        
        if row.source_type != 'Segment' or row.target_type != 'Segment':
            
            link = 0  
            
        else: 
        
            link_one = LF_Contrast_L_L(row)
            
            if link_one:
                
                link = 1
                
            else:
                
                link = 0
   
                    
        finals.append((r_index, link))